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SHARAM PUBLICATION-INTEGRAL CALCULUS-EXAMPLE
- Evaluate: int ((2cosx+7)/(4-sinx))dx
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- Evaluate: int(dx)/(cosx(1+2sinx))
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- Find: int(sin^-1sqrtx-cos^-1sqrtx)/(sin^-1sqrtx+cos^-1sqrtx)dx
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- Integrate:intx^2/(x^4+x^2+1)dx
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- Integrate:intcosx/(1+2sinx)dx
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- int0^pi(xdx)/(1+sinx)
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- Evaluate the following integrals int(12sinx-2cosx+3)/(sinx+cosx)dx
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- int(1+x^2)/(xsqrt(x^4+1))dx
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- int(sqrttanx+sqrtcotx)dx
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- Integrate:int(sinx)/(sin4x)dx
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- What is intfrac[sin^8x-cos^8x][1-2sin^2xcos^2x]dx?
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- Evaluate :int-pi^pi(2x(1+sinx))/(1+cos^2x)dx
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- Integrat:int1/(sinx+sin2x)dx
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- Integrate: int(x^2-3x+1)/(sqrt(1-x^2))dx
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- int(pi//6)^(pi//3)dx/(1+sqrtcotx)
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- int0^pi(xsinxdx)/(1+cos^2x)
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- Show that int0^1(log(1+x))/(1+x^2)dx=pi/8log2
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- Integrate:int(sin^4x-cos^4x)dx
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- int(2sinx+3cosx)/(3sinx+4cosx)dx=?
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- Evaluate the following integrals : int(dx)/((x-2)sqrt(x^(2)-16x+64))
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