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Prove that sin^-1(4/5)+ sin^-1(5/13)+ si...

Prove that `sin^-1(4/5)+ sin^-1(5/13)+ sin^-1(16/65)= pi/2`

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Prove that: sin^(-1)(3/5)+sin^(-1)(8/17)=tan^(-1)(77/36) .

Prove that: cos^(-1)(12/13)+sin^(-1)(3/5)=sin^(-1)(56/65)

Prove that: cos^(-1)(4/5)+cos^(-1)(12/13)=cos^(-1)(33/65)

Prove that sin^(-1)((3)/(5)) + sin^(-1)((8)/(17)) = cos^(-1)((36)/(85)) .

Prove that ( cos^(-1) ""(3)/(5) + sin^(-1)""(5)/(13) ) = sin^(-1)((63)/(65))

Prove that sin( cos^(-1) ""(3)/(5) + sin^(-1)""(5)/(13) ) = (63)/(65)

Solve: sin^(-1)(1-x)-2 sin^(-1)x = pi/2

Solve: 2sin^(-1) x +sin^(-1) (1-x)= pi/2

2sin^(-1)(4/5)+sin^(-1)(24/25) = __.

Show that "sin"^(-1)(8/17)+"sin"^(-1)(3/5)="cos"^(-1)(36/85) .

SHARAM PUBLICATION-MODEL QUESTION PAPER -1-EXERCISE
  1. Show that f(x)=|x| is continuous at x=0 but not deferentiable at x=0.

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  2. If sin y=(2t)/(1 + t^2),cos x= 1/(sqrt(1+t^2)) then show that (dy)/(dx...

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  3. Find the interval where the function f(x) = sin x + cos x, x in [0, 2p...

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  4. Show that no two normals to a parabola are parallel.

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  5. int(cos2x-cos2alpha)/(cosx-cosalpha)dx

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  6. Integrate: int0^(3/2)[x^2]dx

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  7. Solve : (x+y)dy +(x-y)dx = 0.

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  8. Solve: (x^2-1)dy/dx+2xy=1

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  9. If the sum of two unit vectors is a unit vectors find the magnitude of...

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  10. If veca, vecb and vecc are mutually perpendicular, show that [veca.(ve...

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  11. Find the direction cosines of the line (x + 2)/2 = (2y-7)/6 = (5 -z)/...

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  12. Find the equation of a plane biscting the line segment joining (-1,4,3...

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  13. Find the value of r, if the line  (x-1)/(1) = (y+2)/(3) = (z-1)/(-1) =...

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  14. If (cosx)^(y)=(cosy)^(x), then find (dy)/(dx).

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  15. Evaluate int0^pi x/(a^2 cos^2 x + b^2 sin^2 x) dx

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  16. Find the area bounded by the curve y = sin x from x = 0 to x = pi.

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  17. Show that the inverse of a bijective function is unique.

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  18. Prove that sin^-1(4/5)+ sin^-1(5/13)+ sin^-1(16/65)= pi/2

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  19. If veca, vecb, vecc are mutually perpendicular vectors of equal magnit...

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  20. Find the coordinates of the foot of the perpendicular drawn from the p...

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