Three persons hit a target with probability `1/2,1/3` and `1/4` respectively. If each one shoot at the target once,
find the probability that exactly one of them hits the target

Three persons hit a target with probabilities (1/2) , (1/3) and (1/4) respectively. If each one shoots at the target once, (i) find the probaility that exactly one of them hits the target, (ii) if only one of them hits the target what is the probability that it was the first person?

Three persons hit a target with probability 1/2,1/3 and 1/4 respectively. If each one shoot at the target once, if only one of them hits the target what is the probability that it was the first person ?

Probability of solving specific problem independently by A and B are 1/2 and 1/3, respectively. If both try to solve the problem independently then find the probability that exactly one of them solves the problem.

The probability of A , B and C solving a problem are (1)/(3) , (2)/(7) and (3)/(8) respectively. If all try and solve the problem simulimeously find the probability that only one of them will solve it.

A man has three children out of them atleast one is boy, then find the probability that he has two boys and one girl.

A can hit a targe: 4 times out of 5 times, B can hit the target 3 times out of 4 times and C can hit the target 2 times out of 3 times. They fire simultaneously. Find the probability that none of them will hit the target.