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If the cube root of unity are 1,omega,om...

If the cube root of unity are `1,omega,omega^(2)`, then the roots of the equation `(x-1)^(3)+8=0` are :

A

-1,-1,-1

B

` -1,-omega,-omega^(2)`

C

`-1,2+3 omega, 2+omega^(2)`

D

`-1,2-3 omega, 2-omega^(2)`

Text Solution

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The correct Answer is:
D
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