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If A=[[a,0,0],[0,a,0],[0,0,a]] then A^n=...

If `A=[[a,0,0],[0,a,0],[0,0,a]]` then `A^n='

A

`[[a^n,0,0],[0,a,0],[0,0,a]]`

B

`[[na,0,0],[0,na,0],[0,0,na]]`

C

`[[a^n,0,0],[0,a^n,0],[0,0,a^n]]`

D

`[[na,0,0],[0,a,0],[0,0,na]]`

Text Solution

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The correct Answer is:
C
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