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If A=[(alpha, beta),(gamma, -alpha)] is ...

If `A=[(alpha, beta),(gamma, -alpha)]` is such that `A^(2)=I`, then

A

`1+alpha^2+beta gamma=0`

B

`1-alpha^2+beta gamma=0`

C

`1-a^2-beta gamma=0`

D

`1+alpha^2-beta gamma=0`

Text Solution

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The correct Answer is:
C
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