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Let Delta=|(1,sintheta,1),(-sin theta,1,...

Let `Delta=|(1,sintheta,1),(-sin theta,1,sintheta),(-1,-sintheta,1)|` , then `Delta` lies in the interval.

A

`[2,3]`

B

`[3,4]`

C

`[2,4]`

D

`(2,4)`

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The correct Answer is:
C
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