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If A=[[sin theta , cos theta],[-cos thet...

If `A=[[sin theta , cos theta],[-cos theta , -sin theta]]` then `A^(2)=`

A

`[[cos 2 theta ,sin 2 theta ] , [-sin 2 theta , -cos 2 theta]]`

B

`[[-cos 2 theta ,sin 2 theta ] , [ sin 2 theta , -cos 2 theta]]`

C

`[[-cos 2 theta ,sin 2 theta ] , [ -sin 2 theta , cos 2 theta]]`

D

`[[-cos 2 theta ,0 ] , [ 0 , -cos 2 theta]]`

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The correct Answer is:
D
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