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Let A= [[5,5 alpha, alpha],[0 ,alpha,5 a...

Let `A= [[5,5 alpha, alpha],[0 ,alpha,5 alpha ],[0,0,5]] |A^(2)|=25,` then `|alpha|=`

A

a)1

B

b)`(1)/(5)`

C

c)1

D

d)`5^(2)`

Text Solution

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The correct Answer is:
B
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