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If A=[(3,2),(1,1)] then A^(2)+xA+yI=0 fo...

If `A=[(3,2),(1,1)]` then `A^(2)+xA+yI=0` for (x,y) =

A

(1,3)

B

(4,-1)

C

(-1,3)

D

(-4,1)

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The correct Answer is:
D
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