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If |[cos(A+B), -sin (A+B), cos 2B],[si...

If `|[cos(A+B), -sin (A+B), cos 2B],[sinA,cosA,sinB],[-cosA,sin A,cos B]|=0` then `B=`

A

`(2n+1) (pi)/(2)`

B

`n pi`

C

`(2 n+1) pi`

D

`2 n pi`

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The correct Answer is:
A
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