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If x is a positive integer, then |[x!...

If `x` is a positive integer, then
`|[x!,(x+1)!,(x+2)!],[(x+1)!,(x+2)!,(x+3)!],[(x+2)!,(x+3)!,(x+4)!]|=`

A

`2 x !(x+1) t`

B

`2 x !(x+1) !(x+2) !`

C

`2 x !(x+3) !`

D

`2(x+1) !(x+2) !(x+3) !`

Text Solution

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The correct Answer is:
B
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