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The locus of the point x=a cos theta, y=...

The locus of the point `x=a cos theta, y=b sin theta` is

A

`(x^(2))/(a^(2))-(y^(2))/(b^(2))=1`

B

`(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`

C

`(x^(2))/(a^(2))+(y^(2))/(b^(2))=2`

D

`a^(2) x^(2)+b^(2) y^(2)=1`

Text Solution

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The correct Answer is:
B
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