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The lines 2 x+3 y=6,2 x+3 y=8 cut the x ...

The lines `2 x+3 y=6,2 x+3 y=8` cut the `x` -axis at `A, B` respectively. A line ' `P` drawn through the point (2,2) meets the `x-` axis at `C,` in such a way that abscissa of `A, B` and `C` are in A.P. Then the equation of the line ' `P` is

A

`2 x+3 y=10`

B

`3 x+2 y=10`

C

`2 x-3 y=10`

D

`3 x-2 y=10`

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The correct Answer is:
A
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