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The equation of the circle whose radius ...

The equation of the circle whose radius is 5 and which passes throngh the points on `x` -axis at distance 3 from the origin is

A

`x^(2)+y^(2) pm 8 y-9=0`

B

`x^(2)+y^(2) pm 8 y+9=0`

C

`x^(2)+y^(2)+8 y pm 9 0`

D

`x^(2)+y^(2)-8 y pm 9=0`

Text Solution

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The correct Answer is:
A
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