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Two vertices of an equilateral trianglt ...

Two vertices of an equilateral trianglt are (-1,0) and (1,0) and its third vertex is above the `x` -axis. The equation of its circum circle is

A

`x^(2)+y^(2)+(2)/(sqrt(3)) x-1=0`

B

`x^(2)+y^(2)-(2)/(sqrt(3)) x-1=0`

C

`x^(2)+y^(2)+(2)/(sqrt(3)) y-1lt0`

D

`x^(2)+y^(2)-(2)/(sqrt(3)) y-1=0`

Text Solution

Verified by Experts

The correct Answer is:
D
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