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If one end of diameter of the circle 2x^...

If one end of diameter of the circle `2x^2+2y^2-4x-8y+2=0` is (3,2) , then the other end is :

A

(2,3)

B

(4,-2)

C

(-1,2)

D

(2,-1)

Text Solution

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The correct Answer is:
C
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