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The equation of the normal at theta=(pi)...

The equation of the normal at `theta=(pi)/(6)` to the hyperbola `3 x^(2)-4 y^(2)=12` is

A

`3 x-y sqrt(3)=7`

B

`3 x+y sqrt(3)=7`

C

`x sqrt(3)+3 y=7`

D

`x sqrt(3)-3 y=7`

Text Solution

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The correct Answer is:
C
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HIMALAYA PUBLICATION-HYPERBOLA-QUESTION BANK
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