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If theta is the angle between the asympt...

If `theta` is the angle between the asymptotes of the hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` with eccentricity is `e` then `sec ((theta)/(2))=`

A

`e^(2)`

B

`e`

C

`2 e`

D

`e^(3)`

Text Solution

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The correct Answer is:
B
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