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2x +sqrt6y=2 touches the hyperbola x^2-2...

`2x +sqrt6y=2` touches the hyperbola `x^2-2y^2=4` , then the point of contact is :

A

`(-2, sqrt(6))`

B

`(-5,2 sqrt(6))`

C

`((1)/(2), (1)/(sqrt(6)))`

D

`(4,-sqrt(6))`

Text Solution

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The correct Answer is:
D
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