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HIMALAYA PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-QUESTION BANK
- 2 tan ^(-1)(-3)=
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- sin ^(-1)[cos (-105^(circ))]=
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- The value of (tan^(-1) ((1)/(2)) + tan^(-1) ((1)/(3)))=
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- tan ^(-1) (1)/(3)+tan ^(-1) (1)/(4)=
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- tan [sin ^(-1) (1)/(sqrt(2))+tan ^(-1) (1)/(2)]=
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- tan ^(-1) (1/11)+tan ^(-1)(2/12)=
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- cot ^(-1)((1)/(5))+cot ^(-1)((1)/(3))-tan ^(-1)((7)/(4))=
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- tan ^(-1) 1+tan ^(-1) 2+tan ^(-1) 3=
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- cot^(-1)(21) +cot^(-1)(13)+co^(-1)(8)=
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- sin ^(-1) (3/5)+sin ^(-1) (8/17)=
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- cos^(-1).(2)/(sqrt(5)) + tan^(-1).(1)/(3) =
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- sin ^(-1)((5)/(13))+tan ^(-1)((12)/(5))=
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- 2 tan ^(-1) (1)/(2)+sin ^(-1) (3)/(5)=
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- sin [sin ^(-1) (2)/(3)+2 cos ^(-1) (2)/(3)]=
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- If tan ^(-1) a^(3)+tan ^(-1) a=tan ^(-1) b, then b=
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- tan ^(-1) (1/3)+tan ^(-1) (1/5)+tan ^(-1) (1/7)=tan ^(-1) x, then x=
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- sin [sin ^(-1)((1-sqrt(3))/(2 sqrt(2)))+cos ^(-1)((sqrt(3)+1)/(2 sqrt(...
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- The value of cos^(-1) ("cos" (5pi)/3)+sin^(-1) ("sin"(5pi)/3) is :
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- sec ^(-1)(cosec 100^(circ))=
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- cos ^(-1)(tan (7 pi)/(4))=
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