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If cos theta=(2 cos phi-1)/(2-cos phi), ...

If `cos theta=(2 cos phi-1)/(2-cos phi)`, then `tan (theta)/(2)=`

A

`sqrt(3) tan (phi)/(2)`

B

`tan (phi)/(2)`

C

`(1)/(sqrt(3)) tan (phi)/(2)`

D

`3 tan (phi)/(2)`

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