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The two lines x=ay+b, z=cy+d and x=a'y+b...

The two lines x=ay+b, z=cy+d and x=a'y+b', z=c'y+d' are perpendicular to each other if :

A

`a/a^(') = c/c^(') = -1`

B

`a/a^(') = c/c^(') = 1`

C

`aa^(') + cc^(') =-1`

D

`aa^(') + cc^(') =1`

Text Solution

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The correct Answer is:
C
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