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The two lines x=ay+b, z=cy+d and x=a'y+b...

The two lines x=ay+b, z=cy+d and x=a'y+b', z=c'y+d' are perpendicular to each other if :

A

`aa^(') + `cc^(') = 1

B

`aa^(') + cc^(') = -1

C

`ab + cd = a^(')b^(') + c^(')d^(')`

D

`aa^(') + bb^(') = cc^(') + dd^(')`

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The correct Answer is:
B
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