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HIMALAYA PUBLICATION-LIMITS, CONTINUITY AND DIFFERENTIABILITY-QUESTION BANK
- lim(x rarr 0) (tan^(-1)3x-4tanx)/(4 sin^(-1) 2x -7x) =
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- lim(x rarr 0) (tan^(-1)7x)/(sin 4x) =
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- lim(x rarr 0) (sin(4x)/(5x) )=
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- lim(x rarr 0) (sin^(2)(x/4))/(x^(2)) =
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- lim(x rarr 0) (1-cos 4x)/(x2) =
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- lim(x rarr 0) (1-cos 4x)/(x2) =
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- lim(x rarr 0) (1-cos 5x)/(sin 4x) =
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- lim(x rarr 0) (1-cos 5x)/(sin^(-1) 2x) =
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- lim(x rarr 0) (1-cos 5x)/(sin3x . tan 2x) =
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- lim(x rarr 0) (1-cos (x/3))/(x^(2)) =
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- lim(x rarr 0) (1-cos(4x)^3) / (5x . tan (2x)) =
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- lim(theta rarr 0) (cos5 theta - cos 7 theta )/(theta^(2)) =
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- lim(x rarr 0) (cos 2x - cos 7x )/(sin 3x . tan 5x) =
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- lim(x rarr 0) (cos 9x - cos 7x )/(x^(2)) =
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- lim(x rarr 0) (cos^(3) 2x - cos ^(3) 3x )/(x^(2)) =
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- lim(x rarr 0) (tan x - sin x)/(x^(3)) =
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- lim(x rarr 0) (tan^(3)2 x - sin^(3) 2x)/(x^(5)) =
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- lim(theta rarr 0) (1-cos theta)/(theta sin theta) =
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- lim(x rarr pi/2)(sec x - tan x)=
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- lim(alpha rarr beta)(sin^(2) alpha - sin^(2)beta)/(alpha^(2)-beta^(2))...
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