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f(x) = (x^(3)+x^(2)-16x+20)/(x-2)^2, x n...

`f(x) = (x^(3)+x^(2)-16x+20)/(x-2)^2, x ne 2`. The value which should be assigned to f(x) at x = 2, so that f(x) is continuous at x = 2 is

A

0

B

2

C

3

D

7

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The correct Answer is:
A
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