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If y = (1+ 1/x)^(x), then dy/dx =...

If `y = (1+ 1/x)^(x)`, then dy/dx =

A

`x(1+1/x)^(x-1).(-1/x^(2))`

B

`(1+1/x)^(x).log((1+x)/x)`

C

`y.[log(1+1/x)-1/(1+x)]`

D

`y[1/(1+x)+log (1+1/x)]`

Text Solution

Verified by Experts

The correct Answer is:
C
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