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If f(x)=x^(alpha) logx and f(0)=0, then ...

If `f(x)=x^(alpha) logx and f(0)=0`, then the value of `alpha` for which Roll's theorem can be applied in [0, 1] is :

A

(-2)

B

(-1)

C

0

D

(1/2)

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The correct Answer is:
D
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