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HIMALAYA PUBLICATION-INDEFINITE INTEGRAL-QUESTION BANK
- int (x+sinx)/(1+cosx)dx is equal to
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- int( (2+ cos(x/2))/(x + sin( x/2) ))dx =
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- int (sinx . cos x)/(sin^(4)x + cos^(4)x) dx =
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- int (1+cos 2x)/(1-cos 2x) dx =
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- int (cos 2x)/(sin^(2)x cos^(2)x) dx =
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- int1/(cos 2x +sin^(2)x) dx =
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- int(cos x)/(sqrt(1 + sin x)) dx.
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- int dx/(1+sin 2x) =
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- int (sin theta + cos theta)/(sqrt(sin 2 theta) ) d theta =
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- int sinx . e^(cosx) dx =
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- int (sin 5x)/(sqrt(cos 5x)) dx =
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- int (sin x dx)/(1+4 cosx) =
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- int (sinx cosx)/(1+ cos 2x) dx =
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- int dx /(x(log x)^(3)) =
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- int e^(sin^(2)x). sin 2x dx =
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- Find int(sinx)/(sin(x-a))dx
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- int sec^(5)x tanx dx
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- int(sec^(2)xdx)/(log (tan x)^(tanx)) =
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- int (e^(sqrtx).cose^(sqrtx))/(sqrtx)dx =
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- int (e^(x) (1+x))/(sin^(2)(xe^(x))) dx =
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