int [1+2 tanx (tanx + sec x)]^(1/2) dx =...

`int [1+2 tanx (tanx + sec x)]^(1/2) dx =`

A

log [sec x . (sec x - tan x)]

B

log [cosec x . (sec x + tan x)]

C

log [sec x. (sec x + tan x)]

D

log [(sec x + tan x)]

Text Solution

Verified by Experts

The correct Answer is:

C

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