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int (cosx dx)/((sinx-1)(sin x-2))=...

`int (cosx dx)/((sinx-1)(sin x-2))=`

A

log ((sin x-1) (sin x-2))+C

B

log ((sinx-2)/(sin x-1))+C

C

log ((sin x-1)/(sin x-2))+C

D

1/2 log ((sin x-1)/(sin x-2))+C

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • int (2cosxdx)/(sinx+cosx)

    A
    1/2x + 1/2 log (sinx+cos x)
    B
    x-log (sinx+cosx)
    C
    x+log(sinx+cosx)
    D
    2log (sinx+cosx)

  • int (cos 2x)/(cosx+sinx)^(2)dx =

    A
    (-1)/(sinx+cos x)+c
    B
    log(sinx+cosx)+c
    C
    log(sinx-cosx)+c
    D
    `log (sinx +cosx)^(2)+c`

  • int dx/(1-cosx -sinx) =

    A
    `log (1+cot (x/2)+c`
    B
    `log (1-tan (x/2)+c`
    C
    `log (1-cot (x/2)+c`
    D
    `log (1+tan (x/2)+c`

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    Explore conceptually related problems

    int (2sinxdx)/(sinx +cosx) =

    int (sec x dx)/(a cosx + b sinx) =

    int (cosx + x sin x)/(x (x + cos x)) dx =

    d/dx {(cosx + sinx)/(cos x - sin x)} =

    int (sin x dx)/(1+4 cosx) =

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