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int (2sinx-cosx)/(2cosx+sinx)dx =...

`int (2sinx-cosx)/(2cosx+sinx)dx =`

A

-log (sinx +2cos x)+C

B

1/2 log (sin x+2cos x)+C

C

2log (sinx+2cos x)+C

D

log (1/(sinx+2cosx))+C

Text Solution

Verified by Experts

The correct Answer is:
D
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