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int (2sinx-cosx)/(2cosx+sinx)dx =...

`int (2sinx-cosx)/(2cosx+sinx)dx =`

A

`4/29 x -19/29log(2cosx + 5 sin x)`

B

`4/29 x +19/29log(2cosx + 5 sin x)`

C

`(-)4/29 x +19/29log(2cosx + 5 sin x)`

D

`(-)4/29 x -19/29log(2cosx + 5 sin x)`

Text Solution

Verified by Experts

The correct Answer is:
C
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