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int (cos4x+1)/(cotx-tanx) dx = A cos 4x ...

`int (cos4x+1)/(cotx-tanx) dx = A cos 4x + B`then

A

A =-1/2

B

A =-1/8

C

A= -1/4

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
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