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HIMALAYA PUBLICATION-INDEFINITE INTEGRAL-QUESTION BANK
- int a^(sqrtx)/sqrtx dx =
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- int (1+x+sqrt(x+x^(2)))/(sqrtx + sqrt(1+x)) dx =
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- int (sin^(3)x+cos^(3)x)/(sin^(2)x. Cos^(2)x )dx =
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- int(x+1)/(x(xe^(x)+1)^(2))dx =
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- int (1)/((1+x^(2))sqrt(1-x^(2)))dx is equal to
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- int (e^(2x) - 2e^(x))/(e^(2x)+1) dx =
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- int(sinxcosx)/(sqrt(1-sin^(4)x)) dx=
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- int(secx)/(secx+tanx)dx=
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- int f(x) dx = g(x), then int f(x)g(x) dx =
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- inte^(tan^(-1)x)(1+x/(1+x^(2)))dx is equal to
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- int cosec(x-a)cosecx dx =
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- If int(sqrtx)/(x(x+1))dx=ktan^(-1)m,then (k,m) is
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- If f(x) sin xcos x dx=(1)/(2(b^(2)-a^(2))*(log f(x))+C, where C is a c...
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- inte^(x)[(sinx+cosx)/(1-sin^(2)x)]dx is
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- When xgt0, then intcos^(-1)((1-x^(2))/(1+x^(2)))dx is
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- int(x^(2) + 1)/(x^(4) + 1) dx =
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- int e^(x)[(1+sinx cosx)/(cos^(2)x)]dx
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- int (10^(pi/2)dx)/(sqrt(10^(-x)-10^(x)) ) =
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- int e^(log(tan x) dx =
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- int (e^(tan^(-1)x))/(1+x^2) dx.
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