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If int (e^(x)-1)/(e^(x)+1) dx = f(x) + c...

If `int (e^(x)-1)/(e^(x)+1) dx = f(x) + c` then f(x) =

A

`2log(e^(x)+1)`

B

`log(e^(2x)-1)`

C

`2log(e^(x)+1)-x`

D

`log(e^(2x)+1)`

Text Solution

Verified by Experts

The correct Answer is:
C
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