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int0^(pi/2) log|tanx+cotx|dx =...

`int_0^(pi/2) log|tanx+cotx|dx =`

A

`pi log 2`

B

`- pi log 2`

C

`pi/2 log 2`

D

`-pi/2 log 2`

Text Solution

Verified by Experts

The correct Answer is:
A
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