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HIMALAYA PUBLICATION-Definite Integrals and its Application-QUESTION BANK
- int(-pi/2)^(pi/2) cos x. sinh x dx =
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- int0^(pi/2) log ((a+b sin x)/(a+b cos x)) dx =
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- int3^(4) sqrt((x-3)(4-x)) dx =
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- int(-a)^(a) x^(n) (a+x) dx, when n is odd =
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- int(-pi/2)^(pi/2) sin^(m) x. cos^(n) x dx = 0, if
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- int0^(2pi) sin^(m) x. cos^(n) x dx = 4 int0^(pi/2) sin^(m) x. cos^(n) ...
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- The value of alpha which satisfies int(pi/2)^(alpha) sin alpha dx = si...
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- int(-pi)^(pi) (sin^(4)x dx) /(sin^(4)x + cos^(x) x) =
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- int0^(pi) e^(cos^(2)).cos^(3) 5x dx =
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- int(1/2)^(2)1/x cosec^(101)(x-1/x) dx =
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- int(-pi/2)^(pi/2) sin^(8) x (6x^(7)-4x^(5)+3x^(3)+2x) dx =
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- If f(a + b - x) = fx, then inta^b x f(x) dx is equal to :
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- int0^(1)(1-x/(1!) +x^(2)/(2!)-x^(3)/(3!) + ……oo)e^(2x) dx =
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- If f(x) = cos x - cos^(2)x + cos^(3)x + …. to oo int f(x) dx =
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- int(pi/4)^(pi/2) (cot^(4)x + cot^(2)x) dx =
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- If In = int0^(pi//4) tan^n x dx, then lim(n to oo) n [In + I(n -2)] eq...
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- If I(n) = int0^(pi/4) tan^(n)x dx, then n(I(n-1)+I(n+1)) =
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- If I(n) = int0^(pi/2) sin^(n)x dx then I(n)/(I(n-2)) =
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- int(1/sqrt3)^(x) (dx)/(1+x^(2)) = pi/6, then the upper limit x =
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- If int0^(k) (dx)/(2+8x^(2)) = pi/16 then k =
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