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HIMALAYA PUBLICATION-Definite Integrals and its Application-QUESTION BANK
- int0^(1) (1-x)/(1+x) dx =
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- int(-1)^(1) tan^(-1) x dx =
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- int0^(pi/2) sin^(6)x. cos^(5) x dx =
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- int0^(pi) cos^(3) x dx=
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- int0^(pi/4) (tan^(4)x + tan^(2)x ) dx =
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- If f(x) is integrable on [0,a], then int0^(a) (f(x))/(f(x)+ f(a-x)) dx...
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- int0^(1) x/((1-x)^(5/4)) dx =
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- int(-1)^(1) (ax^(3)+bx)dx =0 for
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- int0^(pi/2) sin^(8)x. cos^(2)x dx =
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- int(-pi/2)^(pi/2) sin^(4)x. cos^(6)x dx =
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- int2^(3) (dx)/(x^(2)-x) =
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- int0^(3) (3x+1)/(x^(2)+9) dx=
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- int0^(1) sin (2 tan^(-1) sqrt((1+x)/(1-x))) dx =
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- int0^(1) (theta sin theta)/(1+ cos^(2) theta) d theta =
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- int0^(pi/2) (200sinx+100 cosx)/(sin x+ cos x) dx =
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- int(-1)^(1) (coshx)/(1+e^(2x)) dx =
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- int0^(pi//2)(dx)/(1 + tanx)=
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- The value of int(-pi/4)^(pi/4) x^(3) sin^(4) x dx =
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- int0^(pi/2) sin 2x. Log (tan x ) dx =
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- If f(t) is an odd function then int0^(x) f(t( dt is
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