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lim(n to oo) [1/(n^2) "sec"^2 1/(n^2) + ...

`lim_(n to oo) [1/(n^2) "sec"^2 1/(n^2) + 2/(n^2) "sec"^(2) 4/(n^2) + …… + 1/n "sec"^(2) 1]` equals :

A

1/2 cosec 1

B

1/2 sec 1

C

1/2 tan 1

D

tan 1

Text Solution

Verified by Experts

The correct Answer is:
C
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