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Let f(x) = int1^x sqrt(2 - t^2)dt. Then ...

Let `f(x) = int_1^x sqrt(2 - t^2)dt`. Then the real roots of the equation `x^2 - f' (x) = 0` are :

A

`+-1`

B

`+- 1/sqrt2`

C

`+- 1/2`

D

0 and 1

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The correct Answer is:
A
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