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If bar (E )and bar(F) are complementary...

If `bar (E )and bar(F) ` are complementary events of events E and F respectively and ` 0 lt P(F) lt 1 ` , then :

A

P(E|F) + P(E|F) =1

B

P(E|F) + P(E|F) =1

C

`P(bar E |F) + P(E | bar F) =1`

D

`P(bar E | bar F) + P(bar E |F) =1

Text Solution

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The correct Answer is:
A
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