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Out of 3 n consecutive integers, three a...

Out of 3 n consecutive integers, three are selected at random. Find the probability that their sum is divisible by 3 is

A

`(n(3n^(2)-3n+2))/2`

B

`(3n^(2) - 3n +2)/(2(3n-1)(3n-2))`

C

`(3n^(2)-3n+2)/(3n-1)(3n-2)`

D

(n(3n-1)(3n-2))/(3(n-1))

Text Solution

Verified by Experts

The correct Answer is:
C
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