If `lambda_(1) and lambda_(2)` denote the wavelength of de-broglie waves for electron in Bohr's first and second orbits in the hydrogen atom, then `lambda_(1)//lambda_(2)` will be

If lambda1 and lambda2 denote the wavelengths of de Broglie waves for electrons in the first and second Bohr orbits in a hydrogen atom,then lambda1/ lambda2 is equal to

If lamda_1 and lamda_2 denote the wavelength of de Broglie waves for electrons in the first and second Bohr orbits in a hydrogen atom, the (lamda_1)/(lamda_2) is equal to

The de-Broglie's wavelength of an electron in first orbit of Bohr's hydrogen is equal to

The de-Broglie wavelength lambda_(n) of the electron in the n^(th) orbit of hydrogen atom is

de-Broglie wavelength lambda is

Three energy levels P,Q,R of a certain atom are such that E_(P)ltE_(Q)ltE_(R) . If lambda_(1),lambda_(2) and lambda_(3) are the wave length of radiation to transition RtoQ , QtoP and Rto P respectively . The correct relationship between lambda_(1),lambda_(2) and,lambda_(3) is

If lambda_1 and lambda_2 , are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of lambda_1:lambda_2 is:

If lambda_(1)= and lambda_(2) are the wavelengths of the first members of Lyman and Paschen series respectively, then lambda_(1): lambda_(2) , is

If lambda_(1), lambda_(2), lambda_(3) are the wavelengths of the waves giving resonance in the fundamental, first and second overtone modes respecively in a open organ pipe, then the ratio of the wavelengths lambda_(1) : lambda_(2) : lambda_(3) , is :

de-Broglie wave length of Bohr's first orbit is lambda.What is the circumference of third orbit?