A simple pendulum of length 'L' has mass 'M' and it oscillates freely with amplitude energy is
(g = acceleration due to gravity)

A simple pendulum of length l is made to oscillate with an amplitude of 45 degrees. The acceleration due to gravity is g. Let T_(0) = 2pi sqrt(l//g) . The time period of oscillation of this pendulum will be -

A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed ?

A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed ?

Attempt any SIX : A simple pendulum of length 1 m and mass 10 g oscillates freely with amplitude 2 cm. Find its potential energy (P.E.) at the extreme position. (g = 9.8 m//s^(2))

A simple pendulum with a bob of mass ‘m’ oscillates from A to C and back to A such that PB is H . If the acceleration due to gravity is ‘g’ then the velcoity of the bob as it passes through B is

A simple pendulum with a bob of mass m oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is g, then the velocity of the bob as it passes through B is

A simple pendulum with a bob of mass m oscillates from A to C and back to A, such that PB=h, If the acceleration due to gravity is 'g', then the velocity of the bob as it passes through B is

A simple pendulum of length 1 m, and energy 0.2 J, oscillates with an amplitude 4 cm. When its length is doubled then the energy of oscillation will be