Simplify: [`frac{1}{1-2i}`+`frac{3}{1+i}`] [`frac{3+i}{2-4i}`]

Simplify: i^68 + frac{1}{i^145}

Amplitude of frac{1+i}{1-i} is

(frac{1+i}{1-i})^2 =?

If z_1=1-2i , z_2=1+i and z_3=3+4i , then [frac{1}{z_1}+frac{3}{z_2}][frac{z_3}{z_2}=

Reduce( frac{1}{1-4i} - frac{2}{1+i} frac{3-4i}{5+i} ) to the standard form

Find the real numbers x and y such that frac{x}{1+2i} + frac{y}{3+2i} = frac{5+6i}{-1+8i}

(-frac{1}{2}+frac{sqrt3}{2}i)^1000 =

If z=[frac{sqrt3}{2}+frac{i}{2}]^5+[frac{sqrt3}{2}-frac{i}{2}]^5 , then

Find the modulus of [ frac{1+i}{1-i} - frac{1-i}{1+i} ]

Select and write the most appropriate answer from the given alternative of the following If A = [[2,3],[5,-2]] , then A^-1= i] A^2 ii] frac{1}{19}A iii] frac{1}{17}A iv] frac{1}{15}A