If omega is the cube root of units, then...

If `omega` is the cube root of units, then, (3 + 5`omega` + 3`omega^2`) + (3 + 3`omega` + 5`omega^2`)=?

A

4

B

0

C

-4

D

None of these

Verified by Experts

Similar Questions

Explore conceptually related problems

If omega is a complex cube root of unity, then (2+5omega+2(omega)^2)^6 =

If omega is a complex cube root of unity, then (1-omega+(omega)^2)^3 =

If omega is a complex cube root of unity, then show that: (2 + omega + omega^2)^3 - (1 - 3omega + omega^2)^3 = 65

If omega is a complex cube root of unity, then (1+omega^2)^4=

If omega is a complex cube root of unity, then show that: (a + bomega + comega^2) / (c + aomega + bomega^2) = omega^2

If omega is a complex cube root of unity, show that (3+3 omega+5 omega^2)^6 - (2+6omega+2 omega^2)^3 =0

If omega is a complex cube root of unity, then show that: (3 + 3omega + 5omega^2)^6 - (2 + 6omega + 2omega^2)^3 = 0

If omega is a complex cube root of unity, show that (2- omega )(2- omega^2 ) = 7

If omega is a complex cube root of unity, show that (a+b) + (a omega +b omega^2 )+(a omega^2 +b omega ) =0

If omega is a complex cube root of unity, then show that: (2 - omega) (2 - omega^2) = 7