Find the value of (`frac{1}{omega}`+`frac{1}{omega^2}`),where `omega` is the complex cube root of unity.

The value of frac{1}{1+omega}+frac{1}{1+(omega)^2} =

The value of (frac{1+omega}{(omega)^2}}^3 is

Select and write the correct answer from the given alternatives in each of the following: The value of (1 + omega / omega^2)^3 is ( omega is complex cube root of unity)

The value of (1-omega+(omega)^2)(1-(omega)^2+omega)^6 , where omega,(omega)^2 are the cube roots of unity is

If omega is a complex cube root of unity, then (1+omega^2)^4=

Select and write the correct answer from the given alternatives in each of the following:The value of |(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)|,omega being a cube root of unity,is

Select the correct answer from the given alternatives. If omega is a complex cube root of unity then the value of omega^99 + omega^100 + omega^101 is …….. .

If omega is a complex cube root of unity, then (1-omega+(omega)^2)^3 =