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In the figure, DeltaABC is an isosceles ...

In the figure, `DeltaABC` is an isosceles triangle right angled at B. Two equilateral triangles are constructed with sides AC and BC. Then `DeltaBCD`=

A

`/_\ACE`

B

`/_\ABC`

C

`1/2(/_\ABC)`

D

`1/2(/_\ACE)`

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