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VGS PUBLICATION-BRILLIANT-TRIGONOMETRY-EXERCISE
- If sin(A+B)=1 sinB=1/2 then A=
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- sqrt (sec^(2) A + cosec^(2) A ) =
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- If sqrt3 tan theta=1 then theta=
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- sqrt (cosec^(2) theta - sin^(2) theta - cos^(2) theta =
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- cosec 60^(0) ** cos 90^(0) =
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- sin 81^(0)=
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- If sintheta=11/15, then costheta =
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- If tantheta=sqrt3 then sectheta =
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- If 3cottheta=5, then (5sintheta-3costheta)/(5sintheta+3costheta) = ………...
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- (1+tan^2theta)cos^2theta = …………
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- (sec^2theta-1) (cosec^2theta-1)=………….
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- cot^(2) theta - 1/ sin^(2) theta =
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- Show that sqrt (sec^2 O/ + cosec^2 O/) = tan O/ + cot O/
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- (costheta)/(1-tantheta)+(sintheta)/(1-cottheta) = …………….
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- (sintheta-2sin^3theta)/(2cos^3theta-costheta) = …………….
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- sec^2theta+cosec^2theta = ……………….
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- (cosectheta-cottheta)^2 = ……………..
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- (1)/(sectheta-tantheta) = ……………….
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- (tan^2theta)/(1+tan^2theta) = ……………..
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- The value of sin29^@-cos61^@ is …………..
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